c++ - What is the best practice of using itoa() -

c++ - What is the best practice of using itoa() -

when utilize itoa() needs char* _dstbuff, best practice here?

#include "stdafx.h" #include <iostream> using namespace std; int main() { int num = 100; // i'm sure here no memory leak, needs know length. char a[10]; // causue memory leak? if yes, how avoid it? // , why can itoa(num, b, 10); excuted correctly since b // has allocated 1 char. char *b = new char; // difference between char *c , char *b // both can used correctly in itoa() function char *c = new char[10]; itoa(num, a, 10); itoa(num, b, 10); itoa(num, c, 10); cout << << endl; cout << b << endl; cout << c << endl; homecoming 0; }

the output is: 100 100 100

so explain differenct between char *b = new char; , char *c = new char[10]; here?

i know char *c dynamiclly allocate 10 chars, means char *b dynamically allocate 1 char, if i'm right this, why output correct?

actually best practice of a, b, or c?

best practice: don't utilize @ all.

why? because it's not in standard.

what should instead? utilize std::to_string.

(if you're stuck having utilize itoa, utilize big local static buffer, char[512] or -- if want really really safe can create array size sizeof(unsigned long long int) * char_bit + 2 or can hold number expressed in base, plus sign.)

c++ memory-leaks memory-management itoa