shell - Explain how many processes created? -

shell - Explain how many processes created? -

could reply how many processes created in each case commands below dont understand :

the next 3 commands have same effect:

rm $(find . -type f -name '*.o') find . -type f -name '*.o' | xargs rm find . -type f -name '*.o' -exec rm {} \;

exactly 2 processes - 1 rm, other find. 3 or more processes. 1 find, xargs, , 1 or more rm. xargs read standard input, , if reads more lines can passed parameters programme (there maximum value named arg_max). many processes, 1 find , 1 each file ending in .o rm.

in opinion, alternative 2 best, because handles maximum parameter limit correctly , doesn't spawn many processes. however, prefer utilize (with gnu find , xargs):

find . -type f -name '*.o' -print0 | xargs -0 rm

this terminates each filename \0 instead of newline, since filenames in unix can legally contain newlines. handles spaces in filenames (much more common) correctly.

shell process find